Base | Representation |
---|---|
bin | 11111111000011000110001… |
… | …011100111011111101010111 |
3 | 200101110100200212201222211121 |
4 | 133320120301130323331113 |
5 | 121334232422443430143 |
6 | 1214113324101544411 |
7 | 41351102600246512 |
oct | 3770306134737527 |
9 | 611410625658747 |
10 | 140214332014423 |
11 | 40749623050a67 |
12 | 13886588115107 |
13 | 6031202068384 |
14 | 268a5a49cdd79 |
15 | 113246acc87ed |
hex | 7f863173bf57 |
140214332014423 has 2 divisors, whose sum is σ = 140214332014424. Its totient is φ = 140214332014422.
The previous prime is 140214332014403. The next prime is 140214332014441. The reversal of 140214332014423 is 324410233412041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140214332014423 - 25 = 140214332014391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140214332014403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70107166007211 + 70107166007212.
It is an arithmetic number, because the mean of its divisors is an integer number (70107166007212).
Almost surely, 2140214332014423 is an apocalyptic number.
140214332014423 is a deficient number, since it is larger than the sum of its proper divisors (1).
140214332014423 is an equidigital number, since it uses as much as digits as its factorization.
140214332014423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 140214332014423 its reverse (324410233412041), we get a palindrome (464624565426464).
The spelling of 140214332014423 in words is "one hundred forty trillion, two hundred fourteen billion, three hundred thirty-two million, fourteen thousand, four hundred twenty-three".
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