Base | Representation |
---|---|
bin | 11111111000011000110101… |
… | …110001001100000111011111 |
3 | 200101110100212221000012120002 |
4 | 133320120311301030013133 |
5 | 121334233100013313401 |
6 | 1214113335210044515 |
7 | 41351104436633504 |
oct | 3770306561140737 |
9 | 611410787005502 |
10 | 140214404432351 |
11 | 4074965aa13697 |
12 | 138865a841973b |
13 | 6031214072612 |
14 | 268a5b04814ab |
15 | 1132472330a6b |
hex | 7f8635c4c1df |
140214404432351 has 2 divisors, whose sum is σ = 140214404432352. Its totient is φ = 140214404432350.
The previous prime is 140214404432321. The next prime is 140214404432357. The reversal of 140214404432351 is 153234404412041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140214404432351 - 26 = 140214404432287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140214404432357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70107202216175 + 70107202216176.
It is an arithmetic number, because the mean of its divisors is an integer number (70107202216176).
Almost surely, 2140214404432351 is an apocalyptic number.
140214404432351 is a deficient number, since it is larger than the sum of its proper divisors (1).
140214404432351 is an equidigital number, since it uses as much as digits as its factorization.
140214404432351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 184320, while the sum is 38.
Adding to 140214404432351 its reverse (153234404412041), we get a palindrome (293448808844392).
The spelling of 140214404432351 in words is "one hundred forty trillion, two hundred fourteen billion, four hundred four million, four hundred thirty-two thousand, three hundred fifty-one".
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