Base | Representation |
---|---|
bin | 1100110000001100011001… |
… | …0110100000000100001111 |
3 | 1211122111111022221012000021 |
4 | 3030003012112200010033 |
5 | 3314214230331311143 |
6 | 45453355253043011 |
7 | 2645030510166466 |
oct | 314030626400417 |
9 | 54574438835007 |
10 | 14022101041423 |
11 | 4516815534182 |
12 | 16a56b1326467 |
13 | 7a93809c2757 |
14 | 36695d7d19dd |
15 | 194b31339ced |
hex | cc0c65a010f |
14022101041423 has 2 divisors, whose sum is σ = 14022101041424. Its totient is φ = 14022101041422.
The previous prime is 14022101041397. The next prime is 14022101041427. The reversal of 14022101041423 is 32414010122041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14022101041423 - 217 = 14022100910351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14022101041427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7011050520711 + 7011050520712.
It is an arithmetic number, because the mean of its divisors is an integer number (7011050520712).
Almost surely, 214022101041423 is an apocalyptic number.
14022101041423 is a deficient number, since it is larger than the sum of its proper divisors (1).
14022101041423 is an equidigital number, since it uses as much as digits as its factorization.
14022101041423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 14022101041423 its reverse (32414010122041), we get a palindrome (46436111163464).
The spelling of 14022101041423 in words is "fourteen trillion, twenty-two billion, one hundred one million, forty-one thousand, four hundred twenty-three".
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