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14022101041441 is a prime number
BaseRepresentation
bin1100110000001100011001…
…0110100000000100100001
31211122111111022221012000221
43030003012112200010201
53314214230331311231
645453355253043041
72645030510166523
oct314030626400441
954574438835027
1014022101041441
114516815534199
1216a56b1326481
137a93809c276c
1436695d7d1a13
15194b31339d11
hexcc0c65a0121

14022101041441 has 2 divisors, whose sum is σ = 14022101041442. Its totient is φ = 14022101041440.

The previous prime is 14022101041439. The next prime is 14022101041463. The reversal of 14022101041441 is 14414010122041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13300754880400 + 721346161041 = 3647020^2 + 849321^2 .

It is a cyclic number.

It is not a de Polignac number, because 14022101041441 - 21 = 14022101041439 is a prime.

Together with 14022101041439, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14022101041471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7011050520720 + 7011050520721.

It is an arithmetic number, because the mean of its divisors is an integer number (7011050520721).

Almost surely, 214022101041441 is an apocalyptic number.

It is an amenable number.

14022101041441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14022101041441 is an equidigital number, since it uses as much as digits as its factorization.

14022101041441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1024, while the sum is 25.

Adding to 14022101041441 its reverse (14414010122041), we get a palindrome (28436111163482).

The spelling of 14022101041441 in words is "fourteen trillion, twenty-two billion, one hundred one million, forty-one thousand, four hundred forty-one".