Base | Representation |
---|---|
bin | 11111111000100001001111… |
… | …011001010111110101111011 |
3 | 200101111020011112112112120021 |
4 | 133320201033121113311323 |
5 | 121334410033112044011 |
6 | 1214121430221511311 |
7 | 41351544113542501 |
oct | 3770411731276573 |
9 | 611436145475507 |
10 | 140223424331131 |
11 | 40752469466099 |
12 | 138882a5112537 |
13 | 603202099bc2b |
14 | 268abc8396671 |
15 | 11327ee13d471 |
hex | 7f884f657d7b |
140223424331131 has 2 divisors, whose sum is σ = 140223424331132. Its totient is φ = 140223424331130.
The previous prime is 140223424331101. The next prime is 140223424331197. The reversal of 140223424331131 is 131133424322041.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140223424331131 - 213 = 140223424322939 is a prime.
It is a super-2 number, since 2×1402234243311312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (140223424331101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70111712165565 + 70111712165566.
It is an arithmetic number, because the mean of its divisors is an integer number (70111712165566).
Almost surely, 2140223424331131 is an apocalyptic number.
140223424331131 is a deficient number, since it is larger than the sum of its proper divisors (1).
140223424331131 is an equidigital number, since it uses as much as digits as its factorization.
140223424331131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 140223424331131 its reverse (131133424322041), we get a palindrome (271356848653172).
The spelling of 140223424331131 in words is "one hundred forty trillion, two hundred twenty-three billion, four hundred twenty-four million, three hundred thirty-one thousand, one hundred thirty-one".
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