140233434121125 has 32 divisors (see below), whose sum is σ = 259276038203520. Its totient is φ = 74791164862800.

The previous prime is 140233434121037. The next prime is 140233434121127. The reversal of 140233434121125 is 521121434332041.

140233434121125 is a `hidden beast` number, since 1 + 4 + 0 + 2 + 3 + 3 + 434 + 1 + 211 + 2 + 5 = 666.

It is not a de Polignac number, because 140233434121125 - 2²⁴ = 140233417343909 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 140233434121125.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140233434121127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20775320199 + ... + 20775326948.

It is an arithmetic number, because the mean of its divisors is an integer number (8102376193860).

Almost surely, 2^{140233434121125} is an apocalyptic number.

140233434121125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

140233434121125 is a deficient number, since it is larger than the sum of its proper divisors (119042604082395).

140233434121125 is an equidigital number, since it uses as much as digits as its factorization.

140233434121125 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41550647171 (or 41550647155 counting only the distinct ones).

The product of its (nonzero) digits is 69120, while the sum is 36.

Adding to 140233434121125 its reverse (521121434332041), we get a palindrome (661354868453166).

The spelling of 140233434121125 in words is "one hundred forty trillion, two hundred thirty-three billion, four hundred thirty-four million, one hundred twenty-one thousand, one hundred twenty-five".