Base | Representation |
---|---|
bin | 11111111000101010100100… |
… | …000001101100001110100111 |
3 | 200101112012000010201120001002 |
4 | 133320222210001230032213 |
5 | 121340041033113334002 |
6 | 1214130203354223515 |
7 | 41352350140420634 |
oct | 3770524401541647 |
9 | 611465003646032 |
10 | 140233434121127 |
11 | 40756735757506 |
12 | 1388a219424b9b |
13 | 6032c577064a9 |
14 | 268b49794718b |
15 | 1132bd7cd2002 |
hex | 7f8aa406c3a7 |
140233434121127 has 2 divisors, whose sum is σ = 140233434121128. Its totient is φ = 140233434121126.
The previous prime is 140233434121037. The next prime is 140233434121181. The reversal of 140233434121127 is 721121434332041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140233434121127 - 230 = 140232360379303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140233434121427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70116717060563 + 70116717060564.
It is an arithmetic number, because the mean of its divisors is an integer number (70116717060564).
Almost surely, 2140233434121127 is an apocalyptic number.
140233434121127 is a deficient number, since it is larger than the sum of its proper divisors (1).
140233434121127 is an equidigital number, since it uses as much as digits as its factorization.
140233434121127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 38.
Adding to 140233434121127 its reverse (721121434332041), we get a palindrome (861354868453168).
The spelling of 140233434121127 in words is "one hundred forty trillion, two hundred thirty-three billion, four hundred thirty-four million, one hundred twenty-one thousand, one hundred twenty-seven".
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