140240004401381 has 2 divisors, whose sum is σ = 140240004401382. Its totient is φ = 140240004401380.

The previous prime is 140240004401377. The next prime is 140240004401423. The reversal of 140240004401381 is 183104400042041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130405094445025 + 9834909956356 = 11419505^2 + 3136066^2 .

It is a cyclic number.

It is not a de Polignac number, because 140240004401381 - 2² = 140240004401377 is a prime.

It is a super-2 number, since 2×140240004401381² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140240004401681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70120002200690 + 70120002200691.

It is an arithmetic number, because the mean of its divisors is an integer number (70120002200691).

Almost surely, 2^{140240004401381} is an apocalyptic number.

It is an amenable number.

140240004401381 is a deficient number, since it is larger than the sum of its proper divisors (1).

140240004401381 is an equidigital number, since it uses as much as digits as its factorization.

140240004401381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12288, while the sum is 32.

The spelling of 140240004401381 in words is "one hundred forty trillion, two hundred forty billion, four million, four hundred one thousand, three hundred eighty-one".