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140254231253 is a prime number
BaseRepresentation
bin1000001010011111001…
…1011011101011010101
3111102000120002011110112
42002213303123223111
54244220040400003
6144233142532405
713063426203203
oct2024763335325
9442016064415
10140254231253
1154532947914
1223222a37105
13102c24565a6
146b072ca073
1539ad1de3d8
hex20a7cdbad5

140254231253 has 2 divisors, whose sum is σ = 140254231254. Its totient is φ = 140254231252.

The previous prime is 140254231207. The next prime is 140254231289. The reversal of 140254231253 is 352132452041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77942589124 + 62311642129 = 279182^2 + 249623^2 .

It is a cyclic number.

It is not a de Polignac number, because 140254231253 - 224 = 140237454037 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140254231553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70127115626 + 70127115627.

It is an arithmetic number, because the mean of its divisors is an integer number (70127115627).

Almost surely, 2140254231253 is an apocalyptic number.

It is an amenable number.

140254231253 is a deficient number, since it is larger than the sum of its proper divisors (1).

140254231253 is an equidigital number, since it uses as much as digits as its factorization.

140254231253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 140254231253 its reverse (352132452041), we get a palindrome (492386683294).

The spelling of 140254231253 in words is "one hundred forty billion, two hundred fifty-four million, two hundred thirty-one thousand, two hundred fifty-three".