Base | Representation |
---|---|
bin | 11010001000100011… |
… | …10101000101100111 |
3 | 1100012210201111211212 |
4 | 31010101311011213 |
5 | 212213242121341 |
6 | 10240120422035 |
7 | 1004454441305 |
oct | 150421650547 |
9 | 40183644755 |
10 | 14030426471 |
11 | 5a4a8a0086 |
12 | 287691791b |
13 | 1427a02cc9 |
14 | 971557275 |
15 | 571b435eb |
hex | 344475167 |
14030426471 has 2 divisors, whose sum is σ = 14030426472. Its totient is φ = 14030426470.
The previous prime is 14030426393. The next prime is 14030426477. The reversal of 14030426471 is 17462403041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14030426471 - 210 = 14030425447 is a prime.
It is a super-3 number, since 3×140304264713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14030426477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7015213235 + 7015213236.
It is an arithmetic number, because the mean of its divisors is an integer number (7015213236).
Almost surely, 214030426471 is an apocalyptic number.
14030426471 is a deficient number, since it is larger than the sum of its proper divisors (1).
14030426471 is an equidigital number, since it uses as much as digits as its factorization.
14030426471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
The spelling of 14030426471 in words is "fourteen billion, thirty million, four hundred twenty-six thousand, four hundred seventy-one".
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