Base | Representation |
---|---|
bin | 11111111001110010111100… |
… | …010101100111110010000011 |
3 | 200101210121121101111220110212 |
4 | 133321302330111213302003 |
5 | 121342324214230112212 |
6 | 1214230015245344335 |
7 | 41361101063446643 |
oct | 3771627425476203 |
9 | 611717541456425 |
10 | 140311151410307 |
11 | 40786697081119 |
12 | 138a12a88680ab |
13 | 603a39193a737 |
14 | 269114b474523 |
15 | 1134c35b96e22 |
hex | 7f9cbc567c83 |
140311151410307 has 2 divisors, whose sum is σ = 140311151410308. Its totient is φ = 140311151410306.
The previous prime is 140311151410249. The next prime is 140311151410349. The reversal of 140311151410307 is 703014151113041.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140311151410307 is a prime.
It is not a weakly prime, because it can be changed into another prime (140311151440307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70155575705153 + 70155575705154.
It is an arithmetic number, because the mean of its divisors is an integer number (70155575705154).
Almost surely, 2140311151410307 is an apocalyptic number.
140311151410307 is a deficient number, since it is larger than the sum of its proper divisors (1).
140311151410307 is an equidigital number, since it uses as much as digits as its factorization.
140311151410307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 32.
The spelling of 140311151410307 in words is "one hundred forty trillion, three hundred eleven billion, one hundred fifty-one million, four hundred ten thousand, three hundred seven".
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