14033124324281 has 2 divisors, whose sum is σ = 14033124324282. Its totient is φ = 14033124324280.

The previous prime is 14033124324257. The next prime is 14033124324283. The reversal of 14033124324281 is 18242342133041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9891553367056 + 4141570957225 = 3145084^2 + 2035085^2 .

It is a cyclic number.

It is not a de Polignac number, because 14033124324281 - 2⁶ = 14033124324217 is a prime.

It is a super-2 number, since 2×14033124324281² (a number of 27 digits) contains 22 as substring.

Together with 14033124324283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14033124324283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7016562162140 + 7016562162141.

It is an arithmetic number, because the mean of its divisors is an integer number (7016562162141).

Almost surely, 2^{14033124324281} is an apocalyptic number.

It is an amenable number.

14033124324281 is a deficient number, since it is larger than the sum of its proper divisors (1).

14033124324281 is an equidigital number, since it uses as much as digits as its factorization.

14033124324281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 110592, while the sum is 38.

The spelling of 14033124324281 in words is "fourteen trillion, thirty-three billion, one hundred twenty-four million, three hundred twenty-four thousand, two hundred eighty-one".