Base | Representation |
---|---|
bin | 1100110000110101101111… |
… | …1101100111010000111101 |
3 | 1211200120010220112020200121 |
4 | 3030031123331213100331 |
5 | 3314404443431044201 |
6 | 45502432532254541 |
7 | 2645602542444661 |
oct | 314153375472075 |
9 | 54616126466617 |
10 | 14033201034301 |
11 | 45204a1159109 |
12 | 16a788a771451 |
13 | 7aa42c55a587 |
14 | 3672d3a908a1 |
15 | 195080a7b9a1 |
hex | cc35bf6743d |
14033201034301 has 2 divisors, whose sum is σ = 14033201034302. Its totient is φ = 14033201034300.
The previous prime is 14033201034283. The next prime is 14033201034341. The reversal of 14033201034301 is 10343010233041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12146437810276 + 1886763224025 = 3485174^2 + 1373595^2 .
It is an emirp because it is prime and its reverse (10343010233041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14033201034301 - 217 = 14033200903229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14033201034341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7016600517150 + 7016600517151.
It is an arithmetic number, because the mean of its divisors is an integer number (7016600517151).
Almost surely, 214033201034301 is an apocalyptic number.
It is an amenable number.
14033201034301 is a deficient number, since it is larger than the sum of its proper divisors (1).
14033201034301 is an equidigital number, since it uses as much as digits as its factorization.
14033201034301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 14033201034301 its reverse (10343010233041), we get a palindrome (24376211267342).
The spelling of 14033201034301 in words is "fourteen trillion, thirty-three billion, two hundred one million, thirty-four thousand, three hundred one".
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