Base | Representation |
---|---|
bin | 11111111010000110011101… |
… | …001011010001011100000010 |
3 | 200101212121200120110022010102 |
4 | 133322012131023101130002 |
5 | 121343200121440041010 |
6 | 1214243402304202402 |
7 | 41362442225663000 |
oct | 3772063513213402 |
9 | 611777616408112 |
10 | 140332103440130 |
11 | 40794568a3a248 |
12 | 138a5375609402 |
13 | 603c350628014 |
14 | 2692177d7ba70 |
15 | 11355602baba5 |
hex | 7fa19d2d1702 |
140332103440130 has 64 divisors (see below), whose sum is σ = 294580197446400. Its totient is φ = 48112962492672.
The previous prime is 140332103440099. The next prime is 140332103440183. The reversal of 140332103440130 is 31044301233041.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 140332103440093 and 140332103440102.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 197601137 + ... + 198310043.
It is an arithmetic number, because the mean of its divisors is an integer number (4602815585100).
Almost surely, 2140332103440130 is an apocalyptic number.
140332103440130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
140332103440130 is an abundant number, since it is smaller than the sum of its proper divisors (154248094006270).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
140332103440130 is an equidigital number, since it uses as much as digits as its factorization.
140332103440130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 766648 (or 766634 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 140332103440130 its reverse (31044301233041), we get a palindrome (171376404673171).
The spelling of 140332103440130 in words is "one hundred forty trillion, three hundred thirty-two billion, one hundred three million, four hundred forty thousand, one hundred thirty".
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