14033343041 has 2 divisors, whose sum is σ = 14033343042. Its totient is φ = 14033343040.

The previous prime is 14033343031. The next prime is 14033343043. The reversal of 14033343041 is 14034333041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13298933041 + 734410000 = 115321^2 + 27100^2 .

It is a cyclic number.

It is not a de Polignac number, because 14033343041 - 2²² = 14029148737 is a prime.

Together with 14033343043, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14033343041.

It is not a weakly prime, because it can be changed into another prime (14033343043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7016671520 + 7016671521.

It is an arithmetic number, because the mean of its divisors is an integer number (7016671521).

Almost surely, 2^14033343041 is an apocalyptic number.

It is an amenable number.

14033343041 is a deficient number, since it is larger than the sum of its proper divisors (1).

14033343041 is an equidigital number, since it uses as much as digits as its factorization.

14033343041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 14033343041 its reverse (14034333041), we get a palindrome (28067676082).

The spelling of 14033343041 in words is "fourteen billion, thirty-three million, three hundred forty-three thousand, forty-one".