Base | Representation |
---|---|
bin | 1100110000110110101000… |
… | …1101111101101010011101 |
3 | 1211200120202120120012020022 |
4 | 3030031222031331222131 |
5 | 3314410441142420443 |
6 | 45502512354401525 |
7 | 2645611505361035 |
oct | 314155215755235 |
9 | 54616676505208 |
10 | 14033440201373 |
11 | 452060416294a |
12 | 16a79368902a5 |
13 | 7aa469c79258 |
14 | 36731774a8c5 |
15 | 195096a70e68 |
hex | cc36a37da9d |
14033440201373 has 2 divisors, whose sum is σ = 14033440201374. Its totient is φ = 14033440201372.
The previous prime is 14033440201273. The next prime is 14033440201427. The reversal of 14033440201373 is 37310204433041.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13635161826724 + 398278374649 = 3692582^2 + 631093^2 .
It is a cyclic number.
It is not a de Polignac number, because 14033440201373 - 214 = 14033440184989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14033440201273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7016720100686 + 7016720100687.
It is an arithmetic number, because the mean of its divisors is an integer number (7016720100687).
Almost surely, 214033440201373 is an apocalyptic number.
It is an amenable number.
14033440201373 is a deficient number, since it is larger than the sum of its proper divisors (1).
14033440201373 is an equidigital number, since it uses as much as digits as its factorization.
14033440201373 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72576, while the sum is 35.
The spelling of 14033440201373 in words is "fourteen trillion, thirty-three billion, four hundred forty million, two hundred one thousand, three hundred seventy-three".
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