Base | Representation |
---|---|
bin | 1100110001001111100010… |
… | …0111011001100001011111 |
3 | 1211201020000101200120002002 |
4 | 3030103320213121201133 |
5 | 3320013133243413210 |
6 | 45505535523552515 |
7 | 2646236236420421 |
oct | 314237047314137 |
9 | 54636011616062 |
10 | 14040124201055 |
11 | 45234240a4827 |
12 | 16a90a122b73b |
13 | 7aac93971654 |
14 | 36778d32a811 |
15 | 19533876a4a5 |
hex | cc4f89d985f |
14040124201055 has 64 divisors (see below), whose sum is σ = 17202326400000. Its totient is φ = 10999473408000.
The previous prime is 14040124201043. The next prime is 14040124201073. The reversal of 14040124201055 is 55010242104041.
It is a happy number.
It is not a de Polignac number, because 14040124201055 - 24 = 14040124201039 is a prime.
It is a super-2 number, since 2×140401242010552 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 14082370817 + ... + 14082371813.
It is an arithmetic number, because the mean of its divisors is an integer number (268786350000).
Almost surely, 214040124201055 is an apocalyptic number.
14040124201055 is a deficient number, since it is larger than the sum of its proper divisors (3162202198945).
14040124201055 is a wasteful number, since it uses less digits than its factorization.
14040124201055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2064.
The product of its (nonzero) digits is 6400, while the sum is 29.
Adding to 14040124201055 its reverse (55010242104041), we get a palindrome (69050366305096).
The spelling of 14040124201055 in words is "fourteen trillion, forty billion, one hundred twenty-four million, two hundred one thousand, fifty-five".
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