Search a number
-
+
14040124214327 is a prime number
BaseRepresentation
bin1100110001001111100010…
…0111011100110000110111
31211201020000101201020021122
43030103320213130300313
53320013133244324302
645505535524134155
72646236236504211
oct314237047346067
954636011636248
1014040124214327
1145234241037a2
1216a90a123735b
137aac939776c3
1436778d3315b1
1519533876e3a2
hexcc4f89dcc37

14040124214327 has 2 divisors, whose sum is σ = 14040124214328. Its totient is φ = 14040124214326.

The previous prime is 14040124214321. The next prime is 14040124214329. The reversal of 14040124214327 is 72341242104041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14040124214327 - 222 = 14040120020023 is a prime.

Together with 14040124214329, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14040124214321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7020062107163 + 7020062107164.

It is an arithmetic number, because the mean of its divisors is an integer number (7020062107164).

Almost surely, 214040124214327 is an apocalyptic number.

14040124214327 is a deficient number, since it is larger than the sum of its proper divisors (1).

14040124214327 is an equidigital number, since it uses as much as digits as its factorization.

14040124214327 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43008, while the sum is 35.

Adding to 14040124214327 its reverse (72341242104041), we get a palindrome (86381366318368).

The spelling of 14040124214327 in words is "fourteen trillion, forty billion, one hundred twenty-four million, two hundred fourteen thousand, three hundred twenty-seven".