1404021413 has 2 divisors, whose sum is σ = 1404021414. Its totient is φ = 1404021412.

The previous prime is 1404021383. The next prime is 1404021433. The reversal of 1404021413 is 3141204041.

It is an a-pointer prime, because the next prime (1404021433) can be obtained adding 1404021413 to its sum of digits (20).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1316093284 + 87928129 = 36278^2 + 9377^2 .

It is an emirp because it is prime and its reverse (3141204041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1404021413 - 2¹² = 1404017317 is a prime.

It is a super-2 number, since 2×1404021413² = 3942552256325033138, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1404021433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702010706 + 702010707.

It is an arithmetic number, because the mean of its divisors is an integer number (702010707).

Almost surely, 2^1404021413 is an apocalyptic number.

It is an amenable number.

1404021413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1404021413 is an equidigital number, since it uses as much as digits as its factorization.

1404021413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

The square root of 1404021413 is about 37470.2737246474. The cubic root of 1404021413 is about 1119.7590396274.

Adding to 1404021413 its reverse (3141204041), we get a palindrome (4545225454).

It can be divided in two parts, 14040 and 21413, that added together give a palindrome (35453).

The spelling of 1404021413 in words is "one billion, four hundred four million, twenty-one thousand, four hundred thirteen".