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14040233403433 is a prime number
BaseRepresentation
bin1100110001001111111100…
…0111111110010000101001
31211201020022000011121120121
43030103333013332100221
53320013344222402213
645505554424323241
72646242033550616
oct314237707762051
954636260147517
1014040233403433
11452347a801126
1216a9111913521
137aacb0487943
1436779da3550d
1519534313b88d
hexcc4ff1fe429

14040233403433 has 2 divisors, whose sum is σ = 14040233403434. Its totient is φ = 14040233403432.

The previous prime is 14040233403431. The next prime is 14040233403451. The reversal of 14040233403433 is 33430433204041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8905282525584 + 5134950877849 = 2984172^2 + 2266043^2 .

It is an emirp because it is prime and its reverse (33430433204041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14040233403433 - 21 = 14040233403431 is a prime.

Together with 14040233403431, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14040233403431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7020116701716 + 7020116701717.

It is an arithmetic number, because the mean of its divisors is an integer number (7020116701717).

Almost surely, 214040233403433 is an apocalyptic number.

It is an amenable number.

14040233403433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14040233403433 is an equidigital number, since it uses as much as digits as its factorization.

14040233403433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 34.

Adding to 14040233403433 its reverse (33430433204041), we get a palindrome (47470666607474).

The spelling of 14040233403433 in words is "fourteen trillion, forty billion, two hundred thirty-three million, four hundred three thousand, four hundred thirty-three".