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140402513213 is a prime number
BaseRepresentation
bin1000001011000010100…
…1000101010100111101
3111102101220002200001222
42002300221011110331
54300021020410323
6144300001043125
713100206446134
oct2026051052475
9442356080058
10140402513213
11545a9616296
12232646264a5
13103170a34b1
146b1cc8891b
1539bb22e9c8
hex20b0a4553d

140402513213 has 2 divisors, whose sum is σ = 140402513214. Its totient is φ = 140402513212.

The previous prime is 140402513149. The next prime is 140402513243. The reversal of 140402513213 is 312315204041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 139485816484 + 916696729 = 373478^2 + 30277^2 .

It is a cyclic number.

It is not a de Polignac number, because 140402513213 - 26 = 140402513149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140402513243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70201256606 + 70201256607.

It is an arithmetic number, because the mean of its divisors is an integer number (70201256607).

Almost surely, 2140402513213 is an apocalyptic number.

It is an amenable number.

140402513213 is a deficient number, since it is larger than the sum of its proper divisors (1).

140402513213 is an equidigital number, since it uses as much as digits as its factorization.

140402513213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 140402513213 its reverse (312315204041), we get a palindrome (452717717254).

The spelling of 140402513213 in words is "one hundred forty billion, four hundred two million, five hundred thirteen thousand, two hundred thirteen".