Base | Representation |
---|---|
bin | 10100011011100111111… |
… | …010100011000011001111 |
3 | 11222020002200012110100122 |
4 | 110123213322203003033 |
5 | 141000443324121221 |
6 | 2553002313015155 |
7 | 203303446661201 |
oct | 24334772430317 |
9 | 4866080173318 |
10 | 1404050223311 |
11 | 4a14aa824a8a |
12 | 1a81456b44bb |
13 | a252aa61508 |
14 | 4bd564b4771 |
15 | 267c8a05eab |
hex | 146e7ea30cf |
1404050223311 has 2 divisors, whose sum is σ = 1404050223312. Its totient is φ = 1404050223310.
The previous prime is 1404050223307. The next prime is 1404050223343. The reversal of 1404050223311 is 1133220504041.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (1133220504041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1404050223311 - 22 = 1404050223307 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1404050253311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702025111655 + 702025111656.
It is an arithmetic number, because the mean of its divisors is an integer number (702025111656).
Almost surely, 21404050223311 is an apocalyptic number.
1404050223311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1404050223311 is an equidigital number, since it uses as much as digits as its factorization.
1404050223311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 1404050223311 its reverse (1133220504041), we get a palindrome (2537270727352).
The spelling of 1404050223311 in words is "one trillion, four hundred four billion, fifty million, two hundred twenty-three thousand, three hundred eleven".
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