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1404112123213 is a prime number
BaseRepresentation
bin10100011011101011100…
…110101011010101001101
311222020020222200022001121
4110123223212223111031
5141001110200420323
62553012403440541
7203305131060322
oct24335346532515
94866228608047
101404112123213
114a1531763328
121a8162386151
13a253a825187
144bd607c8b49
15267ce181a5d
hex146eb9ab54d

1404112123213 has 2 divisors, whose sum is σ = 1404112123214. Its totient is φ = 1404112123212.

The previous prime is 1404112123181. The next prime is 1404112123247. The reversal of 1404112123213 is 3123212114041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 877365675684 + 526746447529 = 936678^2 + 725773^2 .

It is a cyclic number.

It is not a de Polignac number, because 1404112123213 - 25 = 1404112123181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1404112123613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702056061606 + 702056061607.

It is an arithmetic number, because the mean of its divisors is an integer number (702056061607).

Almost surely, 21404112123213 is an apocalyptic number.

It is an amenable number.

1404112123213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1404112123213 is an equidigital number, since it uses as much as digits as its factorization.

1404112123213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1404112123213 its reverse (3123212114041), we get a palindrome (4527324237254).

The spelling of 1404112123213 in words is "one trillion, four hundred four billion, one hundred twelve million, one hundred twenty-three thousand, two hundred thirteen".