Base | Representation |
---|---|
bin | 1100110001010011010000… |
… | …1110101010110101010000 |
3 | 1211201022121002122110022012 |
4 | 3030110310032222311100 |
5 | 3320022210313220222 |
6 | 45510223052402052 |
7 | 2646303102515402 |
oct | 314246416526520 |
9 | 54638532573265 |
10 | 14041124351312 |
11 | 4523897710493 |
12 | 16a9320176328 |
13 | 7ab0c2c32036 |
14 | 3678460b6b72 |
15 | 19539647b1e2 |
hex | cc5343aad50 |
14041124351312 has 10 divisors (see below), whose sum is σ = 27204678430698. Its totient is φ = 7020562175648.
The previous prime is 14041124351311. The next prime is 14041124351339. The reversal of 14041124351312 is 21315342114041.
It can be written as a sum of positive squares in only one way, i.e., 9537374533696 + 4503749817616 = 3088264^2 + 2122204^2 .
It is a super-2 number, since 2×140411243513122 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14041124351311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 438785135963 + ... + 438785135994.
Almost surely, 214041124351312 is an apocalyptic number.
It is an amenable number.
14041124351312 is a deficient number, since it is larger than the sum of its proper divisors (13163554079386).
14041124351312 is an equidigital number, since it uses as much as digits as its factorization.
14041124351312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 877570271965 (or 877570271959 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 14041124351312 its reverse (21315342114041), we get a palindrome (35356466465353).
The spelling of 14041124351312 in words is "fourteen trillion, forty-one billion, one hundred twenty-four million, three hundred fifty-one thousand, three hundred twelve".
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