14041433131340 has 24 divisors (see below), whose sum is σ = 29497878473280. Its totient is φ = 5614502986368.

The previous prime is 14041433131331. The next prime is 14041433131459. The reversal of 14041433131340 is 4313133414041.

It is a junction number, because it is equal to n+sod(n) for n = 14041433131297 and 14041433131306.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 129336020 + ... + 129444539.

It is an arithmetic number, because the mean of its divisors is an integer number (1229078269720).

Almost surely, 2^{14041433131340} is an apocalyptic number.

14041433131340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14041433131340 is an abundant number, since it is smaller than the sum of its proper divisors (15456445341940).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14041433131340 is a wasteful number, since it uses less digits than its factorization.

14041433131340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 258783281 (or 258783279 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 14041433131340 its reverse (4313133414041), we get a palindrome (18354566545381).

The spelling of 14041433131340 in words is "fourteen trillion, forty-one billion, four hundred thirty-three million, one hundred thirty-one thousand, three hundred forty".