140421011132020 has 24 divisors (see below), whose sum is σ = 294885603629568. Its totient is φ = 56168122500000.

The previous prime is 140421011131993. The next prime is 140421011132063. The reversal of 140421011132020 is 20231110124041.

It is a junction number, because it is equal to n+sod(n) for n = 140421011131982 and 140421011132000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13514856 + ... + 21528895.

It is an arithmetic number, because the mean of its divisors is an integer number (12286900151232).

Almost surely, 2^{140421011132020} is an apocalyptic number.

140421011132020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

140421011132020 is an abundant number, since it is smaller than the sum of its proper divisors (154464592497548).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140421011132020 is a wasteful number, since it uses less digits than its factorization.

140421011132020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35244111 (or 35244109 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 140421011132020 its reverse (20231110124041), we get a palindrome (160652121256061).

The spelling of 140421011132020 in words is "one hundred forty trillion, four hundred twenty-one billion, eleven million, one hundred thirty-two thousand, twenty".