Base | Representation |
---|---|
bin | 1100110001011010010101… |
… | …1101101011010110100101 |
3 | 1211201111111111101020200121 |
4 | 3030112211131223112211 |
5 | 3320040103133023023 |
6 | 45511135355041541 |
7 | 2646401141304412 |
oct | 314264535532645 |
9 | 54644444336617 |
10 | 14043024111013 |
11 | 4524682012027 |
12 | 16a97704402b1 |
13 | 7ab3366b03c1 |
14 | 36798651b109 |
15 | 19545813cd5d |
hex | cc5a576b5a5 |
14043024111013 has 2 divisors, whose sum is σ = 14043024111014. Its totient is φ = 14043024111012.
The previous prime is 14043024111001. The next prime is 14043024111029. The reversal of 14043024111013 is 31011142034041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9109392403329 + 4933631707684 = 3018177^2 + 2221178^2 .
It is a cyclic number.
It is not a de Polignac number, because 14043024111013 - 29 = 14043024110501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14043024111073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7021512055506 + 7021512055507.
It is an arithmetic number, because the mean of its divisors is an integer number (7021512055507).
Almost surely, 214043024111013 is an apocalyptic number.
It is an amenable number.
14043024111013 is a deficient number, since it is larger than the sum of its proper divisors (1).
14043024111013 is an equidigital number, since it uses as much as digits as its factorization.
14043024111013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 14043024111013 its reverse (31011142034041), we get a palindrome (45054166145054).
The spelling of 14043024111013 in words is "fourteen trillion, forty-three billion, twenty-four million, one hundred eleven thousand, thirteen".
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