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14043231329993 is a prime number
BaseRepresentation
bin1100110001011011000111…
…0100001001111011001001
31211201112000221022001200122
43030112301310021323021
53320041014210024433
645511212120313025
72646406235526365
oct314266164117311
954645027261618
1014043231329993
114524778a85788
1216a9809912775
137ab36a5c4498
143679a5c5c2a5
1519546b421198
hexcc5b1d09ec9

14043231329993 has 2 divisors, whose sum is σ = 14043231329994. Its totient is φ = 14043231329992.

The previous prime is 14043231329983. The next prime is 14043231330047. The reversal of 14043231329993 is 39992313234041.

14043231329993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9878970744889 + 4164260585104 = 3143083^2 + 2040652^2 .

It is a cyclic number.

It is not a de Polignac number, because 14043231329993 - 214 = 14043231313609 is a prime.

It is a super-2 number, since 2×140432313299932 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14043231329983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7021615664996 + 7021615664997.

It is an arithmetic number, because the mean of its divisors is an integer number (7021615664997).

Almost surely, 214043231329993 is an apocalyptic number.

It is an amenable number.

14043231329993 is a deficient number, since it is larger than the sum of its proper divisors (1).

14043231329993 is an equidigital number, since it uses as much as digits as its factorization.

14043231329993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3779136, while the sum is 53.

The spelling of 14043231329993 in words is "fourteen trillion, forty-three billion, two hundred thirty-one million, three hundred twenty-nine thousand, nine hundred ninety-three".