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14043231330047 is a prime number
BaseRepresentation
bin1100110001011011000111…
…0100001001111011111111
31211201112000221022001202122
43030112301310021323333
53320041014210030142
645511212120313155
72646406235526503
oct314266164117377
954645027261678
1014043231330047
114524778a85827
1216a98099127bb
137ab36a5c450a
143679a5c5c303
1519546b4211d2
hexcc5b1d09eff

14043231330047 has 2 divisors, whose sum is σ = 14043231330048. Its totient is φ = 14043231330046.

The previous prime is 14043231329993. The next prime is 14043231330049. The reversal of 14043231330047 is 74003313234041.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14043231330047 - 26 = 14043231329983 is a prime.

Together with 14043231330049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14043231329989 and 14043231330016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14043231330049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7021615665023 + 7021615665024.

It is an arithmetic number, because the mean of its divisors is an integer number (7021615665024).

Almost surely, 214043231330047 is an apocalyptic number.

14043231330047 is a deficient number, since it is larger than the sum of its proper divisors (1).

14043231330047 is an equidigital number, since it uses as much as digits as its factorization.

14043231330047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72576, while the sum is 35.

Adding to 14043231330047 its reverse (74003313234041), we get a palindrome (88046544564088).

The spelling of 14043231330047 in words is "fourteen trillion, forty-three billion, two hundred thirty-one million, three hundred thirty thousand, forty-seven".