14044020100111 has 2 divisors, whose sum is σ = 14044020100112. Its totient is φ = 14044020100110.

The previous prime is 14044020100109. The next prime is 14044020100163. The reversal of 14044020100111 is 11100102044041.

It is a weak prime.

It is an emirp because it is prime and its reverse (11100102044041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14044020100111 - 2¹ = 14044020100109 is a prime.

It is a super-3 number, since 3×14044020100111³ (a number of 40 digits) contains 333 as substring.

Together with 14044020100109, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14044020100171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7022010050055 + 7022010050056.

It is an arithmetic number, because the mean of its divisors is an integer number (7022010050056).

Almost surely, 2^{14044020100111} is an apocalyptic number.

14044020100111 is a deficient number, since it is larger than the sum of its proper divisors (1).

14044020100111 is an equidigital number, since it uses as much as digits as its factorization.

14044020100111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 14044020100111 its reverse (11100102044041), we get a palindrome (25144122144152).

The spelling of 14044020100111 in words is "fourteen trillion, forty-four billion, twenty million, one hundred thousand, one hundred eleven".