Base | Representation |
---|---|
bin | 1000001011001100000… |
… | …1010010010000010011 |
3 | 111102111200011201222201 |
4 | 2002303001102100103 |
5 | 4300111224141201 |
6 | 144303544144031 |
7 | 13101202543234 |
oct | 2026301222023 |
9 | 442450151881 |
10 | 140442412051 |
11 | 5461a097937 |
12 | 23275a68017 |
13 | 10322432c86 |
14 | 6b242b308b |
15 | 39be9b1801 |
hex | 20b3052413 |
140442412051 has 2 divisors, whose sum is σ = 140442412052. Its totient is φ = 140442412050.
The previous prime is 140442412039. The next prime is 140442412063. The reversal of 140442412051 is 150214244041.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (140442412039) and next prime (140442412063).
It is a cyclic number.
It is not a de Polignac number, because 140442412051 - 233 = 131852477459 is a prime.
It is a super-2 number, since 2×1404424120512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (140442442051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70221206025 + 70221206026.
It is an arithmetic number, because the mean of its divisors is an integer number (70221206026).
Almost surely, 2140442412051 is an apocalyptic number.
140442412051 is a deficient number, since it is larger than the sum of its proper divisors (1).
140442412051 is an equidigital number, since it uses as much as digits as its factorization.
140442412051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5120, while the sum is 28.
Adding to 140442412051 its reverse (150214244041), we get a palindrome (290656656092).
The spelling of 140442412051 in words is "one hundred forty billion, four hundred forty-two million, four hundred twelve thousand, fifty-one".
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