Base | Representation |
---|---|
bin | 1100110001100001111001… |
… | …0010001001110111011000 |
3 | 1211201200201202120122122211 |
4 | 3030120132102021313120 |
5 | 3320103231042232100 |
6 | 45512112445124504 |
7 | 2646502313563600 |
oct | 314303622116730 |
9 | 54650652518584 |
10 | 14045051133400 |
11 | 4525522235a41 |
12 | 16aa037259734 |
13 | 7ab59a629331 |
14 | 367ad980bc00 |
15 | 19552608c1ba |
hex | cc61e489dd8 |
14045051133400 has 72 divisors (see below), whose sum is σ = 37986130668420. Its totient is φ = 4815446099520.
The previous prime is 14045051133389. The next prime is 14045051133409. The reversal of 14045051133400 is 433115054041.
It is a super-2 number, since 2×140450511334002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14045051133409) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 716574442 + ... + 716594041.
Almost surely, 214045051133400 is an apocalyptic number.
14045051133400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14045051133400 is an abundant number, since it is smaller than the sum of its proper divisors (23941079535020).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14045051133400 is a wasteful number, since it uses less digits than its factorization.
14045051133400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1433168513 (or 1433168497 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 14045051133400 its reverse (433115054041), we get a palindrome (14478166187441).
The spelling of 14045051133400 in words is "fourteen trillion, forty-five billion, fifty-one million, one hundred thirty-three thousand, four hundred".
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