Base | Representation |
---|---|
bin | 10100011100100001110… |
… | …110010111010001100111 |
3 | 11222022121102011020121121 |
4 | 110130201312113101213 |
5 | 141004441141030111 |
6 | 2553242553554411 |
7 | 203336521456144 |
oct | 24344166272147 |
9 | 4868542136547 |
10 | 1405022205031 |
11 | 4a1959451265 |
12 | 1a8377115a07 |
13 | a265423b723 |
14 | 4c00960b3cb |
15 | 26834000871 |
hex | 14721d97467 |
1405022205031 has 2 divisors, whose sum is σ = 1405022205032. Its totient is φ = 1405022205030.
The previous prime is 1405022205023. The next prime is 1405022205089. The reversal of 1405022205031 is 1305022205041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1405022205031 - 23 = 1405022205023 is a prime.
It is a super-2 number, since 2×14050222050312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1405022204987 and 1405022205005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1405022205001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702511102515 + 702511102516.
It is an arithmetic number, because the mean of its divisors is an integer number (702511102516).
Almost surely, 21405022205031 is an apocalyptic number.
1405022205031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1405022205031 is an equidigital number, since it uses as much as digits as its factorization.
1405022205031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2400, while the sum is 25.
The spelling of 1405022205031 in words is "one trillion, four hundred five billion, twenty-two million, two hundred five thousand, thirty-one".
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