14051104117 has 2 divisors, whose sum is σ = 14051104118. Its totient is φ = 14051104116.

The previous prime is 14051104079. The next prime is 14051104139. The reversal of 14051104117 is 71140115041.

14051104117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7683223716 + 6367880401 = 87654^2 + 79799^2 .

It is an emirp because it is prime and its reverse (71140115041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14051104117 - 2²³ = 14042715509 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14051104091 and 14051104100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14051107117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7025552058 + 7025552059.

It is an arithmetic number, because the mean of its divisors is an integer number (7025552059).

Almost surely, 2^14051104117 is an apocalyptic number.

It is an amenable number.

14051104117 is a deficient number, since it is larger than the sum of its proper divisors (1).

14051104117 is an equidigital number, since it uses as much as digits as its factorization.

14051104117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 560, while the sum is 25.

Adding to 14051104117 its reverse (71140115041), we get a palindrome (85191219158).

The spelling of 14051104117 in words is "fourteen billion, fifty-one million, one hundred four thousand, one hundred seventeen".