14053025520137 has 2 divisors, whose sum is σ = 14053025520138. Its totient is φ = 14053025520136.

The previous prime is 14053025520077. The next prime is 14053025520139. The reversal of 14053025520137 is 73102552035041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9342198363001 + 4710827157136 = 3056501^2 + 2170444^2 .

It is an emirp because it is prime and its reverse (73102552035041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14053025520137 - 2¹⁸ = 14053025257993 is a prime.

Together with 14053025520139, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14053025520137.

It is not a weakly prime, because it can be changed into another prime (14053025520139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7026512760068 + 7026512760069.

It is an arithmetic number, because the mean of its divisors is an integer number (7026512760069).

Almost surely, 2^{14053025520137} is an apocalyptic number.

It is an amenable number.

14053025520137 is a deficient number, since it is larger than the sum of its proper divisors (1).

14053025520137 is an equidigital number, since it uses as much as digits as its factorization.

14053025520137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 126000, while the sum is 38.

Adding to 14053025520137 its reverse (73102552035041), we get a palindrome (87155577555178).

The spelling of 14053025520137 in words is "fourteen trillion, fifty-three billion, twenty-five million, five hundred twenty thousand, one hundred thirty-seven".