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14053903 is a prime number
BaseRepresentation
bin110101100111…
…001000001111
3222110000022221
4311213020033
512044211103
61221120211
7230312323
oct65471017
928400287
1014053903
117a299a6
124859067
132bb0b26
141c1b983
1513791bd
hexd6720f

14053903 has 2 divisors, whose sum is σ = 14053904. Its totient is φ = 14053902.

The previous prime is 14053889. The next prime is 14053909. The reversal of 14053903 is 30935041.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14053903 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14053909) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7026951 + 7026952.

It is an arithmetic number, because the mean of its divisors is an integer number (7026952).

Almost surely, 214053903 is an apocalyptic number.

14053903 is a deficient number, since it is larger than the sum of its proper divisors (1).

14053903 is an equidigital number, since it uses as much as digits as its factorization.

14053903 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 25.

The square root of 14053903 is about 3748.8535580895. The cubic root of 14053903 is about 241.3231490891.

Adding to 14053903 its reverse (30935041), we get a palindrome (44988944).

The spelling of 14053903 in words is "fourteen million, fifty-three thousand, nine hundred three".