Base | Representation |
---|---|
bin | 1100110010000011011011… |
… | …0110010111001110101111 |
3 | 1211202112222010120200111012 |
4 | 3030200312312113032233 |
5 | 3320230200110304403 |
6 | 45520202023015435 |
7 | 2650241353156121 |
oct | 314406666271657 |
9 | 54675863520435 |
10 | 14054053213103 |
11 | 4529321717732 |
12 | 16ab929b9a57b |
13 | 7ac3a3657107 |
14 | 368311205211 |
15 | 1958a1529ed8 |
hex | cc836d973af |
14054053213103 has 2 divisors, whose sum is σ = 14054053213104. Its totient is φ = 14054053213102.
The previous prime is 14054053213037. The next prime is 14054053213159. The reversal of 14054053213103 is 30131235045041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14054053213103 - 220 = 14054052164527 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14054053213103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14054053213183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7027026606551 + 7027026606552.
It is an arithmetic number, because the mean of its divisors is an integer number (7027026606552).
Almost surely, 214054053213103 is an apocalyptic number.
14054053213103 is a deficient number, since it is larger than the sum of its proper divisors (1).
14054053213103 is an equidigital number, since it uses as much as digits as its factorization.
14054053213103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 14054053213103 its reverse (30131235045041), we get a palindrome (44185288258144).
The spelling of 14054053213103 in words is "fourteen trillion, fifty-four billion, fifty-three million, two hundred thirteen thousand, one hundred three".
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