Base | Representation |
---|---|
bin | 1100110010000011100110… |
… | …1101000111110100100111 |
3 | 1211202120002110201201121111 |
4 | 3030200321231013310213 |
5 | 3320230244341403333 |
6 | 45520210453525451 |
7 | 2650242504325162 |
oct | 314407155076447 |
9 | 54676073651544 |
10 | 14054101122343 |
11 | 452934676a647 |
12 | 16ab942043887 |
13 | 7ac3b055c989 |
14 | 368317716ad9 |
15 | 1958a58404cd |
hex | cc839b47d27 |
14054101122343 has 2 divisors, whose sum is σ = 14054101122344. Its totient is φ = 14054101122342.
The previous prime is 14054101122319. The next prime is 14054101122419. The reversal of 14054101122343 is 34322110145041.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14054101122343 - 25 = 14054101122311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14054101102343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7027050561171 + 7027050561172.
It is an arithmetic number, because the mean of its divisors is an integer number (7027050561172).
Almost surely, 214054101122343 is an apocalyptic number.
14054101122343 is a deficient number, since it is larger than the sum of its proper divisors (1).
14054101122343 is an equidigital number, since it uses as much as digits as its factorization.
14054101122343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 14054101122343 its reverse (34322110145041), we get a palindrome (48376211267384).
The spelling of 14054101122343 in words is "fourteen trillion, fifty-four billion, one hundred one million, one hundred twenty-two thousand, three hundred forty-three".
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