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140546345141 is a prime number
BaseRepresentation
bin1000001011100100110…
…1110000100010110101
3111102202220202002101102
42002321031300202311
54300314331021031
6144322135535445
713103604136166
oct2027115604265
9442686662342
10140546345141
1154672825354
12232a482a585
131033ab22a47
146b3400976d
1539c8b917cb
hex20b93708b5

140546345141 has 2 divisors, whose sum is σ = 140546345142. Its totient is φ = 140546345140.

The previous prime is 140546345101. The next prime is 140546345161. The reversal of 140546345141 is 141543645041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 116793062500 + 23753282641 = 341750^2 + 154121^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140546345141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140546345095 and 140546345104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140546345101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70273172570 + 70273172571.

It is an arithmetic number, because the mean of its divisors is an integer number (70273172571).

Almost surely, 2140546345141 is an apocalyptic number.

It is an amenable number.

140546345141 is a deficient number, since it is larger than the sum of its proper divisors (1).

140546345141 is an equidigital number, since it uses as much as digits as its factorization.

140546345141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 115200, while the sum is 38.

The spelling of 140546345141 in words is "one hundred forty billion, five hundred forty-six million, three hundred forty-five thousand, one hundred forty-one".