Base | Representation |
---|---|
bin | 11010001011100001… |
… | …00010111000011111 |
3 | 1100021112102221222121 |
4 | 31011300202320133 |
5 | 212241121134313 |
6 | 10242404523411 |
7 | 1005205462345 |
oct | 150560427037 |
9 | 40245387877 |
10 | 14055255583 |
11 | 5a62909606 |
12 | 28830b0567 |
13 | 142cbb74a5 |
14 | 97497b995 |
15 | 573dea28d |
hex | 345c22e1f |
14055255583 has 2 divisors, whose sum is σ = 14055255584. Its totient is φ = 14055255582.
The previous prime is 14055255547. The next prime is 14055255593. The reversal of 14055255583 is 38555255041.
It is a happy number.
14055255583 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14055255583 - 217 = 14055124511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14055255523) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7027627791 + 7027627792.
It is an arithmetic number, because the mean of its divisors is an integer number (7027627792).
Almost surely, 214055255583 is an apocalyptic number.
14055255583 is a deficient number, since it is larger than the sum of its proper divisors (1).
14055255583 is an equidigital number, since it uses as much as digits as its factorization.
14055255583 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 600000, while the sum is 43.
The spelling of 14055255583 in words is "fourteen billion, fifty-five million, two hundred fifty-five thousand, five hundred eighty-three".
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