Base | Representation |
---|---|
bin | 10100011101000001100… |
… | …011100000010001010010 |
3 | 11222100222111001221022022 |
4 | 110131001203200101102 |
5 | 141012033324211200 |
6 | 2553411435011442 |
7 | 203355640665605 |
oct | 24350143402122 |
9 | 4870874057268 |
10 | 1405554132050 |
11 | 4a2101734972 |
12 | 1a84a5299b82 |
13 | a270a4c1943 |
14 | 4c05a11433c |
15 | 26865a73885 |
hex | 147418e0452 |
1405554132050 has 24 divisors (see below), whose sum is σ = 2616086586900. Its totient is φ = 561844039680.
The previous prime is 1405554132043. The next prime is 1405554132077. The reversal of 1405554132050 is 502314555041.
It can be written as a sum of positive squares in 6 ways, for example, as 836710848961 + 568843283089 = 914719^2 + 754217^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 1405554132050.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9365135 + ... + 9514034.
Almost surely, 21405554132050 is an apocalyptic number.
1405554132050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1405554132050 is a deficient number, since it is larger than the sum of its proper divisors (1210532454850).
1405554132050 is a wasteful number, since it uses less digits than its factorization.
1405554132050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18880670 (or 18880665 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 35.
Adding to 1405554132050 its reverse (502314555041), we get a palindrome (1907868687091).
The spelling of 1405554132050 in words is "one trillion, four hundred five billion, five hundred fifty-four million, one hundred thirty-two thousand, fifty".
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