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1405555252151 is a prime number
BaseRepresentation
bin10100011101000001100…
…111110001101110110111
311222100222120011211210112
4110131001213301232313
5141012034121032101
62553411515013235
7203355653342321
oct24350147615667
94870876154715
101405555252151
114a210232a476
121a84a573a21b
13a270a7c471b
144c05a326611
1526865be56bb
hex147419f1bb7

1405555252151 has 2 divisors, whose sum is σ = 1405555252152. Its totient is φ = 1405555252150.

The previous prime is 1405555252139. The next prime is 1405555252163. The reversal of 1405555252151 is 1512525555041.

It is a balanced prime because it is at equal distance from previous prime (1405555252139) and next prime (1405555252163).

It is a cyclic number.

It is not a de Polignac number, because 1405555252151 - 234 = 1388375382967 is a prime.

It is a super-2 number, since 2×14055552521512 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1405555252099 and 1405555252108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1405555252111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702777626075 + 702777626076.

It is an arithmetic number, because the mean of its divisors is an integer number (702777626076).

Almost surely, 21405555252151 is an apocalyptic number.

1405555252151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1405555252151 is an equidigital number, since it uses as much as digits as its factorization.

1405555252151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 250000, while the sum is 41.

The spelling of 1405555252151 in words is "one trillion, four hundred five billion, five hundred fifty-five million, two hundred fifty-two thousand, one hundred fifty-one".