Base | Representation |
---|---|
bin | 10100011101100100000… |
… | …000110100010000010111 |
3 | 11222102110202212221021212 |
4 | 110131210000310100113 |
5 | 141014224323211211 |
6 | 2553545045532035 |
7 | 203406160562651 |
oct | 24354400642027 |
9 | 4872422787255 |
10 | 1406132241431 |
11 | 4a2378aa1015 |
12 | 1a8626a1401b |
13 | a27a01c46b8 |
14 | 4c0b2bdd6d1 |
15 | 2689b6ba38b |
hex | 14764034417 |
1406132241431 has 2 divisors, whose sum is σ = 1406132241432. Its totient is φ = 1406132241430.
The previous prime is 1406132241383. The next prime is 1406132241439. The reversal of 1406132241431 is 1341422316041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1406132241431 - 210 = 1406132240407 is a prime.
It is a super-2 number, since 2×14061322414312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1406132241439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 703066120715 + 703066120716.
It is an arithmetic number, because the mean of its divisors is an integer number (703066120716).
Almost surely, 21406132241431 is an apocalyptic number.
1406132241431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1406132241431 is an equidigital number, since it uses as much as digits as its factorization.
1406132241431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 32.
Adding to 1406132241431 its reverse (1341422316041), we get a palindrome (2747554557472).
The spelling of 1406132241431 in words is "one trillion, four hundred six billion, one hundred thirty-two million, two hundred forty-one thousand, four hundred thirty-one".
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