Base | Representation |
---|---|
bin | 1000001100000011000… |
… | …1110010100100101111 |
3 | 111110002202111120021021 |
4 | 2003000301302210233 |
5 | 4301044321344101 |
6 | 144342511315011 |
7 | 13110004510225 |
oct | 2030061624457 |
9 | 443082446237 |
10 | 140673231151 |
11 | 5472840a722 |
12 | 2331b21ba67 |
13 | 1035b1bb01b |
14 | 6b46bd8b15 |
15 | 39d4da75a1 |
hex | 20c0c7292f |
140673231151 has 2 divisors, whose sum is σ = 140673231152. Its totient is φ = 140673231150.
The previous prime is 140673231131. The next prime is 140673231157. The reversal of 140673231151 is 151132376041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140673231151 - 25 = 140673231119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140673231157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70336615575 + 70336615576.
It is an arithmetic number, because the mean of its divisors is an integer number (70336615576).
Almost surely, 2140673231151 is an apocalyptic number.
140673231151 is a deficient number, since it is larger than the sum of its proper divisors (1).
140673231151 is an equidigital number, since it uses as much as digits as its factorization.
140673231151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 34.
The spelling of 140673231151 in words is "one hundred forty billion, six hundred seventy-three million, two hundred thirty-one thousand, one hundred fifty-one".
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