Base | Representation |
---|---|
bin | 11010001110011111… |
… | …11100101101101111 |
3 | 1100100021111120112221 |
4 | 31013033330231233 |
5 | 212314021440241 |
6 | 10245100540211 |
7 | 1005631164325 |
oct | 150717745557 |
9 | 40307446487 |
10 | 14080265071 |
11 | 5a75a40604 |
12 | 288b551667 |
13 | 1435132ac2 |
14 | 97800bd15 |
15 | 5761da5d1 |
hex | 3473fcb6f |
14080265071 has 2 divisors, whose sum is σ = 14080265072. Its totient is φ = 14080265070.
The previous prime is 14080265063. The next prime is 14080265093. The reversal of 14080265071 is 17056208041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14080265071 - 23 = 14080265063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14080265371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7040132535 + 7040132536.
It is an arithmetic number, because the mean of its divisors is an integer number (7040132536).
Almost surely, 214080265071 is an apocalyptic number.
14080265071 is a deficient number, since it is larger than the sum of its proper divisors (1).
14080265071 is an equidigital number, since it uses as much as digits as its factorization.
14080265071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 34.
The spelling of 14080265071 in words is "fourteen billion, eighty million, two hundred sixty-five thousand, seventy-one".
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