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14093156313557 is a prime number
BaseRepresentation
bin1100110100010101000110…
…0100110110100111010101
31211220021220021222000002222
43031011101210312213111
53321400241004013212
645550150122112125
72653124360063336
oct315052144664725
954807807860088
1014093156313557
114543968370882
1216b742164b645
137b2c9595a289
1436a18062228d
151968de3e8c72
hexcd1519369d5

14093156313557 has 2 divisors, whose sum is σ = 14093156313558. Its totient is φ = 14093156313556.

The previous prime is 14093156313553. The next prime is 14093156313601. The reversal of 14093156313557 is 75531365139041.

14093156313557 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13106420037841 + 986736275716 = 3620279^2 + 993346^2 .

It is a cyclic number.

It is not a de Polignac number, because 14093156313557 - 22 = 14093156313553 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14093156313499 and 14093156313508.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14093156313553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7046578156778 + 7046578156779.

It is an arithmetic number, because the mean of its divisors is an integer number (7046578156779).

Almost surely, 214093156313557 is an apocalyptic number.

It is an amenable number.

14093156313557 is a deficient number, since it is larger than the sum of its proper divisors (1).

14093156313557 is an equidigital number, since it uses as much as digits as its factorization.

14093156313557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5103000, while the sum is 53.

The spelling of 14093156313557 in words is "fourteen trillion, ninety-three billion, one hundred fifty-six million, three hundred thirteen thousand, five hundred fifty-seven".