Base | Representation |
---|---|
bin | 10100100001001010100… |
… | …111010110000011111101 |
3 | 11222210110101211100221222 |
4 | 110201022213112003331 |
5 | 141100140240213203 |
6 | 2555425013003125 |
7 | 203604066416036 |
oct | 24411247260375 |
9 | 4883411740858 |
10 | 1410001101053 |
11 | 4a3a83954566 |
12 | 1a93266234a5 |
13 | a2c688bb54c |
14 | 4c35c977a8d |
15 | 26a26189038 |
hex | 1484a9d60fd |
1410001101053 has 2 divisors, whose sum is σ = 1410001101054. Its totient is φ = 1410001101052.
The previous prime is 1410001101013. The next prime is 1410001101127. The reversal of 1410001101053 is 3501011000141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1296767505049 + 113233596004 = 1138757^2 + 336502^2 .
It is a cyclic number.
It is not a de Polignac number, because 1410001101053 - 212 = 1410001096957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1410001101013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705000550526 + 705000550527.
It is an arithmetic number, because the mean of its divisors is an integer number (705000550527).
Almost surely, 21410001101053 is an apocalyptic number.
It is an amenable number.
1410001101053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1410001101053 is an equidigital number, since it uses as much as digits as its factorization.
1410001101053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 1410001101053 its reverse (3501011000141), we get a palindrome (4911012101194).
The spelling of 1410001101053 in words is "one trillion, four hundred ten billion, one million, one hundred one thousand, fifty-three".
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