Base | Representation |
---|---|
bin | 10100100001001010100… |
… | …111010110000101000111 |
3 | 11222210110101211101001201 |
4 | 110201022213112011013 |
5 | 141100140240214002 |
6 | 2555425013003331 |
7 | 203604066416203 |
oct | 24411247260507 |
9 | 4883411741051 |
10 | 1410001101127 |
11 | 4a3a83954623 |
12 | 1a9326623547 |
13 | a2c688bb5a8 |
14 | 4c35c977b03 |
15 | 26a26189087 |
hex | 1484a9d6147 |
1410001101127 has 2 divisors, whose sum is σ = 1410001101128. Its totient is φ = 1410001101126.
The previous prime is 1410001101053. The next prime is 1410001101143. The reversal of 1410001101127 is 7211011000141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1410001101127 - 219 = 1410000576839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1410001101167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705000550563 + 705000550564.
It is an arithmetic number, because the mean of its divisors is an integer number (705000550564).
Almost surely, 21410001101127 is an apocalyptic number.
1410001101127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1410001101127 is an equidigital number, since it uses as much as digits as its factorization.
1410001101127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 1410001101127 its reverse (7211011000141), we get a palindrome (8621012101268).
The spelling of 1410001101127 in words is "one trillion, four hundred ten billion, one million, one hundred one thousand, one hundred twenty-seven".
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