Base | Representation |
---|---|
bin | 1100110100101111000011… |
… | …0101100010111101010010 |
3 | 1211220221212211110020110021 |
4 | 3031023300311202331102 |
5 | 3322004023021443010 |
6 | 45553301315254054 |
7 | 2653462124660203 |
oct | 315136065427522 |
9 | 54827784406407 |
10 | 14100123234130 |
11 | 4546912a8137a |
12 | 16b88468aa32a |
13 | 7b383615069b |
14 | 36a641a0b5aa |
15 | 196b9ad7b8da |
hex | cd2f0d62f52 |
14100123234130 has 32 divisors (see below), whose sum is σ = 25482420737280. Its totient is φ = 5617367757120.
The previous prime is 14100123234091. The next prime is 14100123234149. The reversal of 14100123234130 is 3143232100141.
It is a junction number, because it is equal to n+sod(n) for n = 14100123234095 and 14100123234104.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2014491 + ... + 5679649.
It is an arithmetic number, because the mean of its divisors is an integer number (796325648040).
Almost surely, 214100123234130 is an apocalyptic number.
14100123234130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14100123234130 is a deficient number, since it is larger than the sum of its proper divisors (11382297503150).
14100123234130 is a wasteful number, since it uses less digits than its factorization.
14100123234130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3666714.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 14100123234130 its reverse (3143232100141), we get a palindrome (17243355334271).
The spelling of 14100123234130 in words is "fourteen trillion, one hundred billion, one hundred twenty-three million, two hundred thirty-four thousand, one hundred thirty".
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