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141020013100 = 22521410200131
BaseRepresentation
bin1000001101010101110…
…0101010001000101100
3111110222221000220200011
42003111130222020230
54302302110404400
6144441140143004
713121415222301
oct2032534521054
9443887026604
10141020013100
115489613707a
12233b7397a64
13103b4cb8545
146b7aca90a8
153a055578ba
hex20d572a22c

141020013100 has 18 divisors (see below), whose sum is σ = 306013428644. Its totient is φ = 56408005200.

The previous prime is 141020013077. The next prime is 141020013131. The reversal of 141020013100 is 1310020141.

141020013100 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1410200131002 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 705099966 + ... + 705100165.

Almost surely, 2141020013100 is an apocalyptic number.

141020013100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

141020013100 is an abundant number, since it is smaller than the sum of its proper divisors (164993415544).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141020013100 is a wasteful number, since it uses less digits than its factorization.

141020013100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1410200145 (or 1410200138 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 141020013100 its reverse (1310020141), we get a palindrome (142330033241).

The spelling of 141020013100 in words is "one hundred forty-one billion, twenty million, thirteen thousand, one hundred".

Divisors: 1 2 4 5 10 20 25 50 100 1410200131 2820400262 5640800524 7051000655 14102001310 28204002620 35255003275 70510006550 141020013100